x^2+20x-26.45751311=0

Solution for x^2+20x-26.45751311=0 equation:

x^2+20x-26.45751311=0

a = 1; b = 20; c = -26.45751311;
Δ = b2-4ac
Δ = 202-4·1·(-26.45751311)
Δ = 505.83005244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-\sqrt{505.83005244}}{2*1}=\frac{-20-\sqrt{505.83005244}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+\sqrt{505.83005244}}{2*1}=\frac{-20+\sqrt{505.83005244}}{2}
$